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Quiz of the Month (August 2000)

Hector C. Parr

***

SOLUTION TO LAST MONTH'S QUIZ

           1) Time shown = 7:47

           2) 22 times

           3) 21 and 9/11 minutes past 4.

Notes No.3 can easily be solved by forming an equation, but you might prefer this method: At 4 o'clock the angle between the pointers is 120 degrees, so the minute hand must gain 120 degrees on the hour hand to overtake it. Now the minute hand gains 330 degrees in 60 mins. So it gains 120 degrees in 60 X 120/330 = 21 9/11 mins.

THIS MONTH'S QUIZ

  Alan Wilkinson, a local schoolmaster and historian,
  published a booklet a few years ago entitled "Twenty
  Family Walks". In the preface he writes, "The walks are
  short, ranging from a mile and a half to five miles; the 
  average is two and a half miles."

  Using only this information, answer the following:

  1. What is the total length of all twenty walks?

  2. What is the greatest possible number of walks over
      four miles long?

  3. If there are three walks of five miles each, what is
     the greatest possible number of walks less than five
     miles but over two and a half miles?

***

(c) Hector C. Parr (2001)


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